function that return query result
Question
assume that i have a table named mytable with columns:
------------------------
| id | field1 | field2 |
------------------------
and assume i have a html files:
<body>
<?php
include ('connect-db.php');
include ('function.php');
?>
<ul>
<?php
myfunction();
while($row = $result->fetch_assoc()){
echo "<li>".$row['field1']." and ". $row[field2]."</li>";
}
?>
</ul>
</body>
this is my connect-db.php file:
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
$conn=new mysqli($servername, $username, $password, $dbname);
?>
and this is my function.php file:
<?php
function myfunction(){
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
}
?>
How to echo the field1 and field 2? because i have and error
2 answers
solution1
0 ACCPTED 2016-12-11 10:47:02
Any variable used inside a function is by default limited to the local function scope.
You can read more about it here: Variable scope . How to fix it? Pass the $conn as an argument of myfunction , and return the $result .
function myfunction(mysqli $conn) {
$sql = "SELECT * FROM mytable";
return $conn->query($sql);
}
then you can call it with
$result = myfunction($conn);
solution2
0 2016-12-11 10:49:27
Make sure the following changes.....
at main page
<body>
<?php
include ('connect-db.php');
include ('function.php');
?>
<ul>
<?php
$result= myfunction();
while($row = $result->fetch_assoc()){
echo "<li>".$row['field1']." and ". $row[field2]."</li>";
}
?>
</ul>
</body>
At your function file..
<?php
include ('connect-db.php');
function myfunction(){
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
return $result;
}
?>
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