PHP function doesnt return result of my SQL query

Question

I wrote a function in PHP that is supposed to return the result of an SQL query into a variable, so i can use this variable later in the HTML part to show it on the webpage. Unfortunately, nothing shows up on the page, despite the SQL query being right. I don't know what's wrong or what's missing

here is my code

<?php
// Initialize the session
session_start();

// Check if the user is logged in, if not then redirect him to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
    header("location: login.php");
    exit;
}

// Create connection


/* SHOW NOTE */

function show_note($ue){
  $conn = new mysqli("-", "-", "-", "-");
  // Check connection
  if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
  }
  switch ($ue) {
    case "1.1":
      $sql = "SELECT ((SELECT (AVG(note.note)*21) FROM `note` WHERE user = ? AND matiere = 'devweb') + (SELECT (AVG(note.note)*42) FROM `note` WHERE user = ? AND matiere = 'initdev') + (SELECT (AVG(note.note)*6) FROM `note` WHERE user = ? AND matiere = 'econum')) / 60 FROM `note`";
      $stmt = $conn->prepare($sql);
      if ($stmt === false) {
 printf("Message d'erreur : %s\n", $conn->error);
die();
}
      $stmt->bind_param("sss", $_SESSION['username'],$_SESSION['username'],$_SESSION['username']);
      $stmt->execute();
      $result = $stmt->get_result();
      $resultat = $result->fetch_row();
      $conn->close();
      break;
    case "1.2":
      break;
    case "1.3":
      break;
    case "1.4":
      break;
    case "1.5":
      break;
    case "1.6":
      break;

    return $resultat[0];
  }
}

?>

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Welcome</title>
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css">
    <style>
        body{ font: 14px sans-serif; text-align: center; }
        .addnote{ width: 30%; margin: auto; border: solid 2px pink; }
        .shownote{ width: 30%; margin: auto; border: solid 2px green; }
    </style>
</head>
<body>
    <h1 class="my-5">Hi, <b><?php echo htmlspecialchars($_SESSION["username"]); ?></b>. Welcome to our site.</h1>
    <p>
        <a href="reset-password.php" class="btn btn-warning">Reset Your Password</a>
        <a href="logout.php" class="btn btn-danger ml-3">Sign Out of Your Account</a>
    </p>
    <div class="addnote">
      <h2 class="my-5">Ajouter une note</h2>
      <form action="welcome.php" method="post">
        Matière :
        <input type="radio" id="anglais" name="matiere" value="anglais">
        <label for="anglais">Anglais</label>
        <input type="radio" id="mathdisc" name="matiere" value="mathdisc">
        <label for="mathdisc">MathsDisc</label>
        <input type="radio" id="mathfond" name="matiere" value="mathfond">
        <label for="mathfond">MathsFond</label><br>
        Coefficient : <input type="number" name="coeff"><br>
        Note : <input type="number" name="note"><br>
        <input type="submit" name="addnote">
      </form>
    </div>


    <div class="shownote">
      <h2 class="my-5">Vos moyennes</h2>
      <p>UE 1.1 : <?php echo show_note("1.1") ?></p>
    </div>

</body>
</html>

Answer 1

So basically, the return statement was inside the switch statement

Code before:

... 
case "1.6":
      break;

    return $resultat[0];
  }
}

Code after:

 case "1.6":
      break;
   }
   return $resultat[0];
}

Thanks to @akrys for seeing it and telling me that was the problem !

PHP function doesnt return result of my SQL query

Question

1 answers

solution1
0 2022-01-28 23:01:56

PHP function doesnt return result of my SQL query

Question

1 answers

solution1 0 2022-01-28 23:01:56

solution1
0 2022-01-28 23:01:56