Python 3：如何从浮点数创建列表？

Question

Anyone knows how can I solve this issue? I have the following code.

result=[]
for i in range(len(response_i['objcontent'][0]['rowvalues'])):
    lat = response_i['objcontent'][0]['rowvalues'][i][0]
    print(lat)
    for i in lat:
        result.append(i)     
    print (result)

Following is the output of print(lat) :

92.213725
191.586143
228.981615
240.353291

and following is the output of print(result) :

['9', '2', '.', '2', '1', '3', '7', '2', '5', '1', '9', '1', '.', '5', '8',
'6', '1', '4', '3', '2', '2', '8', '.', '9', '8', '1', '6', '1', '5', '2',
'4', '0', '.', '3', '5', '3', '2', '9', '1']

I expected to get the output in following format:

[92.213725, 191.586143, 228.981615, 240.353291]

Anyone knows how to fix this issue?

Thanks

Answer 1

So, your error is that instead of simply adding your latitute to the list, you are iterating over each character of the latitude, as a string, and adding that character to a list.

result=[]
for value in response_i['objcontent'][0]['rowvalues']:
    lat = value[0]
    print(lat)
    result.append(float(lat))

print (result)

Besides that, using range(len(...))) is the way things have to be done in almost all modern languages, because they either don't implement a "for ...each" or do it in an incomplete or faulty way.

In Python, since the beginning it is a given that whenever one wants a for iteration he wants to get the items of a sequence, not its indices (for posterior retrieval of the indices). Some auxiliar built-ins come in to play to ensure you just interate the sequence: zip to mix one or more sequences, and enumerate to yield the indices as well if you need them.