具有两个选项的Countifs

Question

I am trying to use a countifs to count the places where a store number has either "UE" or "RX" attached to it (in addition to if it matches one other piece of criteria). So for example the criteria would be something like "A16= criteria & "500UE" or "600RX".

Here is the formula I have currently:

=COUNTIFS('AUDIT 1'!$C$3:$C$121,$A16,'AUDIT 1'!$A$3:$A$121,"=*UE")

Now I need to add something to the end of this to the effect of:

,'AUDIT 1'!$A$3:$A$121,"=*RX"

But simply adding that results in no count obviously. I understand that, but I'm not sure what revision (or different formula entirely) I should try.

Thanks in advance!

Answer 1

Wrap it ins a SUM() and use an array {} .

=SUM(COUNTIFS('AUDIT 1'!$C$3:$C$121,$A16,'AUDIT 1'!$A$3:$A$121,{"*UE","*RX"}))

It basically does two COUNTIFS and sums the two together.

Answer 2

I like Scott Craner's answer, but perhaps you might find it simpler to just add a second countif

=COUNTIFS('AUDIT 1'!$C$3:$C$121,$A16,'AUDIT 1'!$A$3:$A$121,"=*UE")+COUNTIFS('AUDIT 1'!$C$3:$C$121,$A16,'AUDIT 1'!$A$3:$A$121,"=*RX")

(Edited - originally said Scott's proposal used an array formula, which it does not)