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如何用给定信息标记观察结果

[英]How to mark the observations with given information

Considering the data collected with 5 minutes time interval with a numeric variable a ,and a discret variable acc , which represents if there's any incident happened( 0 for no incident while 1 for incident): 考虑以5分钟的时间间隔收集的数据,其中包含一个数字变量a和一个离散变量acc ,该变量表示是否发生了任何事件( 0为无事件,而1为事件):

a<-c(1:(288*4))
t<-seq(as.POSIXct("2016-01-01 00:05:00"), as.POSIXct("2016-01-05 00:00:00"), by = '5 min')
acc<-rep(0,288*4)
df<-data.frame(t,a,acc)

Now I have another data set which has the time(accurates to 1 sec) at which the incidents happened during the collection period: 现在,我有了另一个数据集,该数据集具有在收集期间发生事件的时间(精确到1秒):

T<-sample(seq(as.POSIXct("2016-01-01 00:05:00"), as.POSIXct("2016-01-05 00:00:00"), by = '1 sec'),size = 5)

I want to mark the nearest 2 prior observation's acc as 1 according to the time in T . 我想根据T的时间将最近的2个先前观察的acc标记为1。 For example, if the incident happened at 2016-01-02 07:13:23 , the observations' acc with t of 2016-01-02 07:05:00 and 2016-01-02 07:10:00 are marked as 1 例如,如果事件发生在2016-01-02 07:13:23 ,观察值acct2016-01-02 07:05:002016-01-02 07:10:00被标记为1

How could I manage to do this? 我怎样才能做到这一点?

ind <- findInterval(T, df$t)
df$acc[c(ind, ind + 1)] <- 1

One way could be: 一种方法是:

library(lubridate)
df$acc=apply(sapply(T,function(x) x %within% interval((df$t - minutes(4)-seconds(59)),(df$t + minutes(4)+seconds(59)))),1,sum)

lubridate allows for the easy manipulation of dates, minutes(x) and seconds(x) adds x minutes or second to a period object. lubridate允许轻松地操作日期, minutes(x)seconds(x)将x分钟或秒添加到周期对象。
interval() is used to create a time interval confined by the time in df$t ± 4min59s. interval()用于创建一个时间间隔,该时间间隔以df$t ±4min59s为单位。
sapply() is used to check if any of the time in T is within the interval. sapply()用于检查T中的任何时间是否在该间隔内。
apply() is used to collapse the results of sapply() (it outputs 1 column for each element in T) apply()用于折叠sapply()的结果(它为T中的每个元素输出1列)

If T contains a value that is exactly equal to one in df$t such as 2016-01-04 12:05:00 CET this will only put 1 for this one. 如果T包含的值恰好等于df$t例如2016-01-04 12:05:00 CET此值仅将1放入。

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