[英]C++ circular dependency on public aliases (typdef/using) defined inside a class/struct
Is there a way to break circular dependencies like the following without moving both using/typedef
aliases outside classes? 有没有一种方法可以打破如下所示的循环依赖关系,而无需在类外移动using/typedef
别名?
// header A.h
#ifdef A
#define A
#include "B.h"
class A {
using ID = uint32_t;
void some_func(B::ID id);
};
#endif A
// header B.h
#ifdef B
#define B
#include "A.h"
class B {
using ID = uint64_t;
void some_func(A::ID id);
};
#endif B
// main.cpp
#include "A.h"
int main() {...}
Assume guard #ifdef
s are present and ID can be a more complex type (a struct
etc.). 假设存在警卫#ifdef
,并且ID可以是更复杂的类型( struct
等)。
Edit: a bit of clarification: alias names are not necessarily the same (ie not ID
). 编辑:需要澄清:别名不一定相同(即,不是ID
)。
Modified example: 修改示例:
// header A.h
#ifdef A
#define A
#include "B.h"
class A {
using SomeAliasInA = uint32_t;
void some_func(B::SomeAliasInB id);
};
#endif A
// header B.h
#ifdef B
#define B
#include "A.h"
class B {
using SomeAliasInB = std::string;
void some_func(A::SomeAliasInA id);
};
#endif B
Create an external file for type definitions: 创建用于类型定义的外部文件:
template<typename T>
struct types{};
class A;
class B;
template<>
struct types<A>{
using alias = std::string;
};
template<>
struct types<B>{
using ID = bool;
using alias_2 = int;
using alias_3 = short;
};
You can then use it like so: 然后可以像这样使用它:
class A{
void foo(types<B>::ID id);
};
class B{
void foo(types<A>::alias id);
};
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