如何在php的preg_replace模式中添加所有这些符号（“”！？；“，./“”）。

Question

I have:

$input = str_replace('/all these symbols/', "", $input);

Can't really understand the pattern syntax for preg_match and preg_replace . Sometimes people use '+ - * ^ $ \\s' and different kind of brackets there. Tried to read the manual, but don't really get it. Can i find somewhere more clear information about all the possibilities of the preg syntax? Thanks in advance.

Answer 1

Just put those characters into character class as shown in below example:

$replaced = preg_replace("/[“”!?;\",.\/”“']/u", " ", "hello!?; “how are you”");
print_r($replaced);

The output:

hello     how are you 

Answer 2

您可以使用方括号，只需要转义正确的字符即可：

echo preg_replace('/[“”!?;",.\/”“\']/', '', 'a!b?c');