将findall正则表达式转换为finditer

Question

I have following regex

'\D*(\d{13,19})\D*'

I would like to extract number from following text:

Data:
4532394639182605   sadada 4716759060363635 assasasas
  dsdsd 4539072249615668 jdhsjhdj
ABCD

When I use this regexp by calling:

regex = re.compile('\D*(\d{13,19})\D*')
a = regex.finditer(text)
b = regex.findall(text) #Yield correct result

Results are different- I want result from findall . I know that finditer match group. But how transform my findall regex to finditer regex?

I need this same result using finditer like in case use findall .

tl;dr

I want extract numbers not other characters.

Answer 1

finditer returns match objects from which the groups can be extracted with the .group method. This is how one usually works with regexes anyway, it's unusual that findall directly returns strings or tuples with the groups.

import re

text = '''Data:
4532394639182605   sadada 4716759060363635 assasasas
  dsdsd 4539072249615668 jdhsjhdj
ABCD'''

regex = re.compile('\D*(\d{13,19})\D*')
for match in regex.finditer(text):
    print(match.group(1))