使用Xcode 8.x定位到iOS 6（iphone3gs）？
[英]Target iOS 6 (iphone3gs) with Xcode 8.x?
问题描述
I maintain an application that is used by people who have iPhone 3gs devices, the phone is actually part of a mobile barcode scanning application, and uses MFI accessory barcode scanner case hardware with the iPhone inside it. 
我维护着一个拥有iPhone 3gs设备的人使用的应用程序，该电话实际上是移动条形码扫描应用程序的一部分，并使用MFI配件条形码扫描仪保护套硬件以及其中的iPhone。
Until Xcode 8 was released, in Xcode 7, I could still build applications as "iOS 6 and up". 在Xcode 8发布之前，在Xcode 7中，我仍然可以将应用程序构建为“ iOS 6及更高版本”。 It seems this was deleted with almost no discussion or documentation on Apple's site. 似乎已删除了该文件，而Apple网站上几乎没有任何讨论或文档。 Targeting older devices, even though the consumer world may have forgotten about them, is still important to me. 尽管消费者世界可能已经忘记了使用旧设备的目标，但对我来说仍然很重要。
Is there a procedure to use a single Xcode version (8.x) latest and still target iOS 6 targets? 是否有使用最新Xcode版本（8.x）并仍以iOS 6为目标的过程？ (Perhaps by importing resource bundle contents from Xcode 7 manually into Xcode 8's resource folders) Or do people now have to install two Xcode versions (7 and 8) and have two branches of their apps to target everything from iOS 6 to current? （也许是通过手动将Xcode 7中的资源包内容导入到Xcode 8的资源文件夹中）还是人们现在是否必须安装两个Xcode版本（7和8）并拥有两个应用程序分支来定位从iOS 6到当前的所有版本？
1 个解决方案
解决方案1
2 已采纳 2017-01-07 20:14:38
As far as I know the minimal iOS version on xCode 8.* is 8.0. 据我所知，xCode 8. *上的最低iOS版本是8.0。 No longer Apple supports iPhones 3 and 4. There is no workaround around this. Apple不再支持iPhone 3和iPhone4。没有解决方法。 Just keep xCode 7. 只需保留xCode 7。
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