如何设置嵌套结构的大小？

Question

I'd like to make a simple database without making a dynamic sized array. I thought nested structure can help me, but so far it's nothing but pain. This was my idea when I started:

#include <stdio.h>
#define MAXDOG 50
#define MAXCHAR 20

    struct allDog {
        int size;
        struct oneDog[MAXDOG] {
            char dogName[MAXCHAR];
            char OwnerName[MAXCHAR];
        };
    };

I'm pretty sure that my problem is the [MAXDOG] part after struct oneDog, can I give a static size somehow to the inner structure?

You can read the part of the exam I try to do below:

The program asks for the Dog's & Owner's name (MAX 50) then prints out the data. You can't use dynamic arrays...

Answer 1

You're overcomplicating things - try this:

#define MAXDOG 50
#define MAXCHAR 20

typedef struct {        // struct which defines one dog
    char dogName[MAXCHAR];
    char ownerName[MAXCHAR];
} Dog;

typedef struct {        // struct which contains array of dogs
    int size;           // no of dogs in array currently
    Dog dogs[MAXDOGS];  // array of up to MAXDOGS dogs
} Dogs;

Answer 2

You sized the type not the member, syntax is:

struct allDog { // type
        int size;
        struct oneDog { // type
            char dogName[MAXCHAR];
            char OwnerName[MAXCHAR];
        } dogs[MAXDOG]; // member
    };

Take care to be consistent with caps in naming, member OwnerName should be written ownerName to be consistent with other members. Types are generally typed AllDog and OneDog , to differentiate in between members and types.