Python：如何不等待线程完成？

Question

So I have some code that waits for X to happen, then creates a thread and does processEmail.

What I am looking for is a way for the code to carry on waiting X even though processEmail is happening in another thread but currently the code just waits for the thread to finish before waiting for X to happen again.

if X happens:
    thread = Thread(target = processEmail.main())
    thread.start()

EDIT: FYI I have nothing that requires the output of processEmail.main() further down the code therefore there is no need for me to wait for its output.

ANSWER Provided by Jean: Remove the () after main.

Answer 1

Problem is that you're actually calling your method when passing it as argument of Thread .

So it executes, but in the current thread, that's why it's working but it's blocking (and since it probably returns None , you get no error from the Thread object, it just blocks)

Remove parentheses to pass the function object, not the result from the call!

thread = Thread(target = processEmail.main)
thread.start()

Note: some IDEs like PyCharm automatically add parentheses to function names. That's a bad idea in that case :)