我在调试时遇到问题，我不知道 C# 的原因是什么

Question

i have two images the first one for product , and the second one for Barcode of product . i use to create product this code

private void button1_Click(object sender, EventArgs e)
    {
        string barcode = CMBIDCAT.Text+"345" + TXTIDP.Text +"012" ;
        Bitmap bitmap = new Bitmap(barcode.Length * 20, 50);
        using (Graphics graphics = Graphics.FromImage(bitmap))
        {
            Font ofont = new Font("code 128", 30);
            PointF point = new PointF(2f, 2f);
            SolidBrush blackbursh = new SolidBrush(Color.Black);
            SolidBrush whitebursh = new SolidBrush(Color.White);
            graphics.FillRectangle(whitebursh, 0, 0, bitmap.Width, bitmap.Height);
            graphics.DrawString("*" + barcode + "*",ofont, blackbursh, point);
        }
        using (DataTable dt = new DataTable())
        {
            PIC2.Image = bitmap;
            PIC2.Height = bitmap.Height;
            PIC2.Width = bitmap.Width;
        }
private void button3_Click(object sender, EventArgs e)
    {
        MemoryStream ms = new MemoryStream();
        PIC1.Image.Save(ms, PIC1.Image.RawFormat);
        byte[] byteImage = ms.ToArray();
        MemoryStream st = new MemoryStream();
        PIC2.Image.Save(st, PIC2.Image.RawFormat);
        byte[] byteImage1 = st.ToArray();

        prd.ADD_PRODUCT(Convert.ToInt32(CMBIDCAT.SelectedValue), TXTIDP.Text, TXTNMP.Text, Convert.ToInt32(TXTFP.Text), Convert.ToInt32(TXTSP.Text), Convert.ToInt32(TXTTP.Text), TXTDES.Text, Convert.ToInt32(TXTQTE.Text), byteImage, byteImage1);
        MessageBox.Show("تمت الاضافة بنجاح ", "عملية الاضافة",MessageBoxButtons.OK , MessageBoxIcon.Information);
    }

i don't know the reason for this issue please any one help me how can i solve this please .

Answer 1

I don't have the rep to just comment. But, should you be using a new MemoryStream for your second image?

According to the MSDN you should not write to a stream that has been written to.

MSDN "Image.Save Method (Stream, ImageFormat)"

Change your code to:

MemoryStream ms = new MemoryStream();
PIC1.Image.Save(ms, PIC1.Image.RawFormat);
byte[] byteImage = ms.ToArray();

MemoryStream ms1 = new MemoryStream();
PIC2.Image.Save(ms1, PIC2.Image.RawFormat);
byte[] byteImage1 = ms1.ToArray();

Hopefully that works. :)

Answer 2

Make sure which value is null while debugging whether the Format or the stream, and consider using the "using" statement with memory stream in order for the resources to be freed like the following :

        byte[] byteImage1;

        using(MemoryStream ms = new MemoryStream())
        {
            PIC1.Image.Save(ms, PIC1.Image.RawFormat);
            byteImage1 = ms.ToArray();
        }

And consider using two memory streams for each image as @Tim.E suggested.