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Python 3.5:使用 TKInter 下拉菜单中的选项分配多个变量

[英]Python 3.5: Assigning multiple variables using choices in TKInter dropdown menu

Thanks to furas I have the following code for ListBox:感谢 furas,我为 ListBox 提供了以下代码:

import tkinter as tk

def on_button():
#     for i, var in enumerate(o_vars):
#         print('OptionMenu {}: {}'.format(i, var.get()))
#     print()

    print('ListBox:', l.curselection())
    for i in l.curselection():
        print('option:', OPTIONS[i])
    print()


# --- main ---

OPTIONS = ["Script 1","Script 2","Script 3","Script 4","Script 5"]

root = tk.Tk()

# --- Listbox ---

tk.Label(root, text='Listbox', bg='#aaa').pack(fill='x')

l = tk.Listbox(root, selectmode='multiple')
l.pack()
l.insert('end', *OPTIONS)

# --- others ---

b = tk.Button(root, text='OK', command=on_button)
b.pack(fill='x')

root.mainloop()

When I run it, it gives me the following pop-up (image shown below).当我运行它时,它给了我以下弹出窗口(如下图所示)。 I then make my selections.然后我做出我的选择。

在此处输入图片说明

This is where I am stuck... I want to say if user selected Script2 print 'script 2'.这就是我被卡住的地方...我想说是否用户选择了 Script2 打印“脚本 2”。 If user selected script 5, print 'script 5'.如果用户选择了脚本 5,则打印“脚本 5”。

Below is the code I tried but it errored out:下面是我试过但出错的代码:

if l.curselection() == 'Script1':
    print ('test')
if l.curselection() == 'Script2':
    print ('test2')

TclError: invalid command name ".92911768" TclError:无效的命令名称“.92911768”

Also, how do I add a "Quit" button below "OK"?另外,如何在“确定”下方添加“退出”按钮?

*Any help is greatly appreciated *任何帮助是极大的赞赏

OptionMenu after closing dropdown menu can display only one option - so it can't select more options.关闭下拉菜单后的OptionMenu只能显示一个选项 - 因此它无法选择更多选项。

So you can use one of this method:因此,您可以使用以下方法之一:

Only with many OptionMenu you can select in which order execute scripts.只有使用许多OptionMenu才能选择执行脚本的顺序。

Example shows all menthods in one window.示例在一个窗口中显示所有方法。

在此处输入图片说明

import tkinter as tk

# --- functions ---

def on_button():
    for i, var in enumerate(o_vars):
        print('OptionMenu {}: {}'.format(i, var.get()))
    print()

    print('ListBox:', l.curselection())
    for i in l.curselection():
        print('option:', OPTIONS[i])
    print()

    print('ChecboxBox:')
    for i, var in enumerate(cb_vars):
        if var.get():
            print('option:', OPTIONS[i])

# --- main ---

OPTIONS = ["Script 1","Script 2","Script 3","Script 4","Script 5"]

root = tk.Tk()

# --- OptionMenu ---

tk.Label(root, text='OptionMenus', bg='#aaa').pack(fill='x')

o_vars = []

for i in range(3):
    var = tk.StringVar(value='- select -')
    o_vars.append(var)
    o = tk.OptionMenu(root, var, *OPTIONS)
    o.pack()

# --- Listbox ---

tk.Label(root, text='Listbox', bg='#aaa').pack(fill='x')

l = tk.Listbox(root, selectmode='multiple')
l.pack()
l.insert('end', *OPTIONS)

# --- Checkbuttons ---

tk.Label(root, text='Checkbuttons', bg='#aaa').pack(fill='x')

cb_vars = []
for x in OPTIONS:
    var = tk.BooleanVar(value=False)
    cb_vars.append(var)
    c = tk.Checkbutton(root, text=x, variable=var)
    c.pack()

# --- others ---

b = tk.Button(root, text='OK', command=on_button)
b.pack(fill='x')

root.mainloop()

Result:结果:

OptionMenu 1: Script 1
OptionMenu 2: Script 3
OptionMenu 3: Script 5

ListBox: (0, 2, 4)
option: Script 1
option: Script 3
option: Script 5

ChecboxBox:
option: Script 1
option: Script 3
option: Script 5

GitHub: furas/python-examples/tkinter/checkbutton-listbox-optionmenu GitHub: furas/python-examples/tkinter/checkbutton-listbox-optionmenu

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