[英]Python 3.5: Assigning multiple variables using choices in TKInter dropdown menu
感謝 furas,我為 ListBox 提供了以下代碼:
import tkinter as tk
def on_button():
# for i, var in enumerate(o_vars):
# print('OptionMenu {}: {}'.format(i, var.get()))
# print()
print('ListBox:', l.curselection())
for i in l.curselection():
print('option:', OPTIONS[i])
print()
# --- main ---
OPTIONS = ["Script 1","Script 2","Script 3","Script 4","Script 5"]
root = tk.Tk()
# --- Listbox ---
tk.Label(root, text='Listbox', bg='#aaa').pack(fill='x')
l = tk.Listbox(root, selectmode='multiple')
l.pack()
l.insert('end', *OPTIONS)
# --- others ---
b = tk.Button(root, text='OK', command=on_button)
b.pack(fill='x')
root.mainloop()
當我運行它時,它給了我以下彈出窗口(如下圖所示)。 然后我做出我的選擇。
這就是我被卡住的地方...我想說是否用戶選擇了 Script2 打印“腳本 2”。 如果用戶選擇了腳本 5,則打印“腳本 5”。
下面是我試過但出錯的代碼:
if l.curselection() == 'Script1':
print ('test')
if l.curselection() == 'Script2':
print ('test2')
TclError:無效的命令名稱“.92911768”
另外,如何在“確定”下方添加“退出”按鈕?
*任何幫助是極大的贊賞
關閉下拉菜單后的OptionMenu
只能顯示一個選項 - 因此它無法選擇更多選項。
因此,您可以使用以下方法之一:
只有使用許多OptionMenu
才能選擇執行腳本的順序。
示例在一個窗口中顯示所有方法。
import tkinter as tk
# --- functions ---
def on_button():
for i, var in enumerate(o_vars):
print('OptionMenu {}: {}'.format(i, var.get()))
print()
print('ListBox:', l.curselection())
for i in l.curselection():
print('option:', OPTIONS[i])
print()
print('ChecboxBox:')
for i, var in enumerate(cb_vars):
if var.get():
print('option:', OPTIONS[i])
# --- main ---
OPTIONS = ["Script 1","Script 2","Script 3","Script 4","Script 5"]
root = tk.Tk()
# --- OptionMenu ---
tk.Label(root, text='OptionMenus', bg='#aaa').pack(fill='x')
o_vars = []
for i in range(3):
var = tk.StringVar(value='- select -')
o_vars.append(var)
o = tk.OptionMenu(root, var, *OPTIONS)
o.pack()
# --- Listbox ---
tk.Label(root, text='Listbox', bg='#aaa').pack(fill='x')
l = tk.Listbox(root, selectmode='multiple')
l.pack()
l.insert('end', *OPTIONS)
# --- Checkbuttons ---
tk.Label(root, text='Checkbuttons', bg='#aaa').pack(fill='x')
cb_vars = []
for x in OPTIONS:
var = tk.BooleanVar(value=False)
cb_vars.append(var)
c = tk.Checkbutton(root, text=x, variable=var)
c.pack()
# --- others ---
b = tk.Button(root, text='OK', command=on_button)
b.pack(fill='x')
root.mainloop()
結果:
OptionMenu 1: Script 1
OptionMenu 2: Script 3
OptionMenu 3: Script 5
ListBox: (0, 2, 4)
option: Script 1
option: Script 3
option: Script 5
ChecboxBox:
option: Script 1
option: Script 3
option: Script 5
GitHub: furas/python-examples/tkinter/checkbutton-listbox-optionmenu
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