如何将数组与反向数组进行比较并检查它们的值是否匹配？

Question

I wrote a program that reverses an array with the strrev() function and checks if its values matches the original one, sort of a palindrome. When the values match, it prints Palindrome , else, Not a palindrome .

But when I compare them, and the values don't match, it still prints Palindrome .

Here is the code:

#include <stdlib.h>
#include <stdio.h>
#include <math.h>
#include <time.h>
#include <string.h>

#define MAX_LEN 100

void palindrom(char string[]);

int main()
{
    char string[MAX_LEN] = { 0 };

    printf("Enter string (max length 100 chars): ");
    fgets(string, MAX_LEN, stdin);
    if(string[strlen(string)-1] == '\n') { string[strlen(string)-1] = 0; }
    palindrom(string);

    return (0);
} 

void palindrom(char string[])
{
    int check = 0;
    check = strcmp(strrev(string), string);
    if (check == 0)
    {
        printf("Palindrome");
    }
    else
    {
       printf("Not a palindrome");
    }
}

What's my problem? Thanks.

Answer 1

从我可以告诉strrev也可以修改原始字符串，所以你需要复制它。

Answer 2

The key is strrev .

Here's a program in C that will do what you're testing for:

#include <stdio.h>
#include <string.h>

int main()
{
   char a[100], b[100];

   printf("Enter the string to check if it is a palindrome\n");
   fgets(a, 100, stdin);

   strcpy(b,a);
   strrev(b);

   if (strcmp(a,b) == 0)
      printf("Entered string is a palindrome.\n");
   else
      printf("Entered string is not a palindrome.\n");

   return 0;
}

Answer 3

Since others have clarified what the problem is, I would like to point that it would be faster to check if s[0] == s[len-1], s[1] == s[len-2], until half (rounded up) of the string has been checked.

This would require no extra memory, no copy and half as many comparisons. Something along the lines of:

void palindrom(char string[])
{
    int len = strlen(string) - 1;
    int i, limit = len/2 + (len % 2);
    for (i = 0; i < limit; i++){
        if (string[i] != string[len-i]){
            printf("Not a palindrome\n");
            return;
        }
    }
    printf("Palindrome\n");
}

Answer 4

Your function fails because strrev modifies the string. You effectively always compare the reversed string to itself.

Here is an alternate function that does not modify the string:

void palindrom(const char *str) {
    for (size_t i = 0, j = strlen(str); i < j; i++, j--) {
        if (str[i] != str[j - 1]) {
            printf("Not a palindrome\n");
            return;
        }
    }
    printf("Palindrome\n");
}

Answer 5

You don't need to use strrev to test for a palindrome the following function detects a palindrome just fine without using non-standard C functions:

int ispalindrome(char *str, int len)
{   
    char *p = &str[0];
    char *q = &str[len - 1];
    do
    {
        if(p >= q)
        {
            return 1;
        }
    } while (*p++ == *q--);
    return 0;
}