laravel 5.3-通过whereIn mysql命令结果

Question

I have looked at most other solutions here but none of them seems to work for me. I have a table with about 100K rows in it.

each row is a record from an iot device, which includes the unique id of that device. The device id may have 10K rows from the 100K.

Reading::whereIn('device_id', $ids)->orderBy('created_at',
 'DESC')->groupBy('device_id')->get()->

I am able to pull out the ids i need and group them together by "device_id" as query above but its picking the first result and not the last for each id.

How can i get the most recent record for each id instead of the oldest?

I have looked at laravel collections and the reverse(), first(), latest(); option but i still cant get it

Any ideas?

UPDATE

The best i have been able to come up with is this query below which does grab the latest record for each device_id

SELECT t1.* FROM readings t1 WHERE t1.id = (SELECT t2.id FROM readings
t2 WHERE t2.device_id = t1.device_id ORDER BY t2.id DESC LIMIT 1)

I'll then loop through those results and grab only the records the user has access to.

Not pretty, but it works for now.

If anyone ever does find away to do it in eloquent please answer

Answer 1

I believe this should work?

Reading::select('device_id', 'id', DB::raw('MAX(created_at) AS latest'))->whereIn('device_id', $ids)->orderBy('latest', 'DESC')->groupBy('device_id')->get();

Hope this helps!

Answer 2

OK, I believe this may work, as previous attempts didn't:

$sub = Reading::orderBy('created_at','desc');

return DB::table(DB::raw("({$sub->toSql()}) as sub"))
    ->whereIn('device_id', $ids)
    ->groupBy('device_id')
    ->get();

You basically run a 'sub query'. So, retrieve the results in the order you need first, then run the second query to group them.

Answer 3

This is kinda a tricky question to think about. Once you re-frame the question in database lingo, something like "get max record for each id in MySQL query", it is quite easy to find a lot of SO answers.

Here's a highly rated example on SO: Retrieving the last record in each group

In your updated query, the subquery is actually recomputed for every row I think. We can do better by joining readings to itself (check above link as reference)

SELECT r1.*
FROM readings r1
  LEFT JOIN readings r2
    ON r2.device_id = r1.device_id
       AND r1.date_created < r2.date_created
WHERE r2.device_id IS NULL # there is no row with a date_created greater than r1's
;

Indexes on device_id and date_created are an easy first step for making this faster

Answer 4

I was finally able to get it sorted out. The following query returns exactly what i want in laravel.

$sql = Reading::select('created_at', 'column1', 'column2', 'column3', 'column4', 'column5',
'column6')->whereIn('device_id', ['0','0'])->toSql(); 

// 0 is just "empty" value, it doesn't matter here yet

$db = DB::connection()->getPdo();
$query = $db->prepare($sql);

// real ids im looking for

$query->execute(array('ffvr5g6h', 'ccvl5f4rty'));


$collection = collect($query);

// change this to take ever (n) record 

//$collection = $collection->every(100);
$collection = $collection->groupBy('device_id');

 foreach ($collection as $collect) {
                // process data
               $end = $collect->last();
               print_r($end);
            }

This query above is querying 100K rows in about half a second, then turning that into a collection for laravel, once in a collection i group by id, then grab the last record from that result.

Thanks to all those who tried to help :)