如何使用bash遍历命令以获取目录中文件数？

Question

Here iam using a bash script which runs like this

for d in os.listdir($folder_name); do
        echo "Running the scanner :"
        python bd.py $folder_name/$d
done

Here iam downloading some files to my directory name folder_name then i want to run the script taking arguments as each and every file name.I tried to use this logic but it failed giving me this error.

./test: line 29: syntax error near unexpected token `('
./test: line 29: `for d in os.listdir($folder_name); do'

Is there any way to repeat the loop taking each file as argument and passing it to the python file.

Answer 1

Presumably, you want to iterate over the files in a directory and run some python script taking each filename as argument; if so, just globbing to get the filenames would do:

for f in /directory/*; do python bd.py "$f"; done

Replace /directory/ with the actual directory name.

os.listdir() is a function from os module in python that returns a list containing the contents of a directory as strings, the same thing you can achieve with simple shell globbing in any shell.