如何创建可以抛出任何异常的通用函数？

Question

I have two classes(structure example):

public class A {
    protected void doCheck(stuff) throw CommonException, A1Exception{
        if(stuff==1){
            throw new A1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeAstuff(stuff) throw CommonException, A1Exception{
        doCheck(stuff);
    }
}
public class B {
    protected void doCheck(stuff) throw CommonException, B1Exception{
        if(stuff==1){
            throw new B1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeBstuff(stuff, otherStuff) throw CommonException, B1Exception{
        doCheck(stuff);
    }
}

"doCheck" methods have same logic for handling stuff, but have 1 different exception which can be thrown by each class: A1Exception for A class and B1Exception for B class

My question is: How I can write basic class which will implement "doCheck" with common logic + take class of exception that should be thrown in some conditions? A and B just should extend this class.

Answer 1

You could make a generic abstract class which declares the exception as a generic type, and then make a supplier method which you must override in the subclasses.

public abstract class Checkable<X extends Exception> {

    protected abstract X getException(int stuff);

    protected void doCheck(int stuff) throws CommonException, X {
        if (stuff == 1) {
            throw this.getException(stuff);
        }
        throw new CommonException(stuff);
    }

}

A subclass would look like:

public class A extends Checkable<A1Exception> {

    @Override
    protected A1Exception getException(int stuff) {
        return new A1Exception(stuff);
    }

    public void invokeStuff(int stuff) {
        doCheck(stuff);
    }

}

Ideone Demo