如何創建可以拋出任何異常的通用函數？

Question

我有兩個類（結構示例）：

public class A {
    protected void doCheck(stuff) throw CommonException, A1Exception{
        if(stuff==1){
            throw new A1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeAstuff(stuff) throw CommonException, A1Exception{
        doCheck(stuff);
    }
}
public class B {
    protected void doCheck(stuff) throw CommonException, B1Exception{
        if(stuff==1){
            throw new B1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeBstuff(stuff, otherStuff) throw CommonException, B1Exception{
        doCheck(stuff);
    }
}

“ doCheck”方法具有相同的邏輯來處理內容，但是每個類可以拋出1個不同的異常：A類為A1Exception，B類為B1Exception

我的問題是：如何編寫將使用通用邏輯實現“ doCheck”的基本類+接受應在某些情況下拋出的異常類？ A和B僅應擴展此類。

Answer 1

您可以創建一個將異常聲明為通用類型的通用抽象類，然后創建一個必須在子類中重寫的供應商方法。

public abstract class Checkable<X extends Exception> {

    protected abstract X getException(int stuff);

    protected void doCheck(int stuff) throws CommonException, X {
        if (stuff == 1) {
            throw this.getException(stuff);
        }
        throw new CommonException(stuff);
    }

}

子類如下所示：

public class A extends Checkable<A1Exception> {

    @Override
    protected A1Exception getException(int stuff) {
        return new A1Exception(stuff);
    }

    public void invokeStuff(int stuff) {
        doCheck(stuff);
    }

}

Ideone演示