JS对象数组删除最后一个空元素

Question

I have that javascript object :

MyObject = [
   {
     "name" : "aaa",
     "firstname" : "aaaaa"
   },
   {
     "name" : "bbb",
     "firstname" : "bbbb"
   },
   {
     "name" : "cccc",
     "firstname" : "" <--------- firstname is empty, but the element is not in the last
   },
   {
     "name" : "ddd",
     "firstname" : "dddd"
   },
   {
     "name" : "eeee",
     "firstname" : ""  <--------- firstname is empty
   },
   {
     "name" : "fffff",
     "firstname" : ""  <--------- firstname is empty
   },
]

I want to delete the lastest lines that have "firstname" empty ... (a sort of trim) ... i dont want to remove all lines that have "firstname" empty... but just who are in the latestes lines. (that are in the bottom)

So, the result will be :

MyObject = [
   {
     "name" : "aaa",
     "firstname" : "aaaaa"
   },
   {
     "name" : "bbb",
     "firstname" : "bbbb"
   },
   {
     "name" : "cccc",
     "firstname" : ""
   },
   {
     "name" : "ddd",
     "firstname" : "dddd"
   }
]

Thank you

Answer 1

You can pop of at the end of the array as long as the firstname is empty

 var MyObject = [{ "name": "aaa", "firstname": "aaaaa" }, { "name": "bbb", "firstname": "bbbb" }, { "name": "cccc", "firstname": "" }, { "name": "ddd", "firstname": "dddd" }, { "name": "eeee", "firstname": "" }, { "name": "fffff", "firstname": "" }]; for (var i=MyObject.length;i--;) if (MyObject[i].firstname==="") MyObject.pop(); else break; console.log(MyObject) 

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Answer 2

Try this:

 var MyObject = [ { "name" : "aaa", "firstname" : "aaaaa" }, { "name" : "bbb", "firstname" : "bbbb" }, { "name" : "cccc", "firstname" : "" }, { "name" : "ddd", "firstname" : "dddd" }, { "name" : "eeee", "firstname" : "" }, { "name" : "fffff", "firstname" : "" } ]; var i = MyObject.length; while(true) { if (!MyObject[--i].firstname) { MyObject.pop(); } else { break; } } console.log(MyObject);