JS对象数组删除最后一个空元素

Question

我有那个javascript对象：

MyObject = [
   {
     "name" : "aaa",
     "firstname" : "aaaaa"
   },
   {
     "name" : "bbb",
     "firstname" : "bbbb"
   },
   {
     "name" : "cccc",
     "firstname" : "" <--------- firstname is empty, but the element is not in the last
   },
   {
     "name" : "ddd",
     "firstname" : "dddd"
   },
   {
     "name" : "eeee",
     "firstname" : ""  <--------- firstname is empty
   },
   {
     "name" : "fffff",
     "firstname" : ""  <--------- firstname is empty
   },
]

我想删除具有“ firstname”为空的最新行 ...（一种修整）...我不想删除具有“ firstname”为空的所有行...，而是那些最新行中的人。 （在底部）

因此，结果将是：

MyObject = [
   {
     "name" : "aaa",
     "firstname" : "aaaaa"
   },
   {
     "name" : "bbb",
     "firstname" : "bbbb"
   },
   {
     "name" : "cccc",
     "firstname" : ""
   },
   {
     "name" : "ddd",
     "firstname" : "dddd"
   }
]

谢谢

Answer 1

您可以在数组末尾弹出，只要名字为空

 var MyObject = [{ "name": "aaa", "firstname": "aaaaa" }, { "name": "bbb", "firstname": "bbbb" }, { "name": "cccc", "firstname": "" }, { "name": "ddd", "firstname": "dddd" }, { "name": "eeee", "firstname": "" }, { "name": "fffff", "firstname": "" }]; for (var i=MyObject.length;i--;) if (MyObject[i].firstname==="") MyObject.pop(); else break; console.log(MyObject) 

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Answer 2

尝试这个：

 var MyObject = [ { "name" : "aaa", "firstname" : "aaaaa" }, { "name" : "bbb", "firstname" : "bbbb" }, { "name" : "cccc", "firstname" : "" }, { "name" : "ddd", "firstname" : "dddd" }, { "name" : "eeee", "firstname" : "" }, { "name" : "fffff", "firstname" : "" } ]; var i = MyObject.length; while(true) { if (!MyObject[--i].firstname) { MyObject.pop(); } else { break; } } console.log(MyObject);