[英]Map<Enum, Integer> map2 = new EnumMap<what-to-write-to-make-compile???>(map1);
class Enum is defined in API as:类 Enum 在 API 中定义为:
public abstract class Enum<E extends Enum<E>>
I have我有
enum Cards { Trefs(2.3), Clubs(1.0);
public double d;
private Cards(double val) {
this.d = val;
}
}
Question 1:问题 1:
Enum e = Cards.Clubs; //compiles, but with warning: "References to generic type Enum<E> should be parameterized"
Enum<???what-shall-I-write-here??> e1 = Cards.Clubs; //Question 1
Question 2:问题2:
this compiles:这编译:
Map<Enum, Integer> map0 = new HashMap<Enum, Integer>();
Map<Enum, Integer> map1 = new HashMap<Enum, Integer>();
map1.put(Cards.Clubs, new Integer(54));
Map<Enum, Integer> map2 = new EnumMap<>(map1);
But can I add anything in angle brackets of RHS (new EnumMap), like I did for map1 above?但是我可以在 RHS(新 EnumMap)的尖括号中添加任何内容,就像我在上面的 map1 中所做的那样?
Map<Enum, Integer> map2 = new EnumMap<???what-can-I-write-here??>(map1);
PS I researched SO, but found nothing DIRECTLY answering above question. PS我研究了SO,但没有发现直接回答上述问题。 My research:
我的研究:
First: please use this instead:第一:请改用这个:
Cards e = Cards.Clubs;
Second: Use the diamond operator .第二:使用菱形运算符。 If you absolutely want, it is
new EnumMap<Cards, Integer>()
but why do you want to write it out?如果你绝对想要,它是
new EnumMap<Cards, Integer>()
但是你为什么要写出来呢? And please never use new Integer(54)
.并且请永远不要使用
new Integer(54)
。 If for whatever reason you do not like autoboxing , use Integer.valueOf(54)
instead.如果出于某种原因您不喜欢autoboxing ,请改用
Integer.valueOf(54)
。 It doesn't waste objects . 它不会浪费对象。
So, I recommend this code:所以,我推荐这个代码:
Map<Cards, Integer> map0 = new HashMap<>();
Map<Cards, Integer> map1 = new HashMap<>();
map1.put(Cards.Clubs, 54);
Map<Cards, Integer> map2 = new EnumMap<>(map1);
The first thing is:第一件事是:
Enum<Cards> e = Cards.Clubs;
Map<Enum<Cards>, Integer> map0 = new HashMap<>();
Map<Enum<Cards>, Integer> map1 = new HashMap<>();
map1.put(Cards.Clubs, 54);
But I don't know why the Map<Enum<Cards>, Integer> map2 = new EnumMap<>(map1);
但我不知道为什么
Map<Enum<Cards>, Integer> map2 = new EnumMap<>(map1);
fails失败
Edit:编辑:
So I think what you want is something like this:所以我认为你想要的是这样的:
Cards e = Cards.Clubs;
Map<Cards, Integer> map0 = new HashMap<>();
Map<Cards, Integer> map1 = new HashMap<>();
map1.put(Cards.Clubs, 54);
EnumMap<Cards, Integer> map2 = new EnumMap<>(map1);
You don't need to wrap you Enum into an Enum你不需要把你的 Enum 包装成一个 Enum
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.