用于在字符串中查找 mp4 的正则表达式

Question

I want to get all .mp4 URLs of this String using Regex.

Also I want to know how to get only the last .mp4 URL using Regex.

Thanks

contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}, 

Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}, 

Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}, 

Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}, 

Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]";

Answer 1

Regex:

https?.*?\.mp4

Literal http

Followed by an optional 's': s?

Remove the question mark if they will all use HTTPS.

Followed by as few characters as possible: .*?

Followed by an mp4 extension (literal dot) \\.mp4

Answer 2

2 Approaches:

1. If you're sure the URL's will always begin with https:// and will not contain a mp4 after the complete URL is finished, then you can use pattern = "https://.*mp4";

    String[] arr = { "contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}", "Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}", "Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}", "Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}", "Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]" }; String pattern = "https://.*mp4"; Pattern r = Pattern.compile(pattern); for (String line : arr) { Matcher m = r.matcher(line); if (m.find()) { System.out.println(m.group(0)); } else { System.out.println("NO MATCH"); } }

2. If not, to Support all types of URL's then change your pattern to what is defined here with a little modification,

    String pattern = "(((ht|f)tp(s?)\\\\:\\\\/\\\\/|~\\\\/|\\\\/)|www.)" + "(\\\\w+:\\\\w+@)?(([-\\\\w]+\\\\.)+(com|org|net|gov" + "|mil|biz|info|mobi|name|aero|jobs|museum" + "|travel|[az]{2}))(:[\\\\d]{1,5})?" + "(((\\\\/([-\\\\w~!$+|.,=]|%[af\\\\d]{2})+)+|\\\\/)+|\\\\?|#)?" + "((\\\\?([-\\\\w~!$+|.,*:]|%[af\\\\d{2}])+=?" + "([-\\\\w~!$+|.,*:=]|%[af\\\\d]{2})*)" + "(&(?:[-\\\\w~!$+|.,*:]|%[af\\\\d{2}])+=?" + "([-\\\\w~!$+|.,*:=]|%[af\\\\d]{2})*)*)*" + "(#([-\\\\w~!$+|.,*:=]|%[af\\\\d]{2})*)?\\\\b"+"mp4";

Output:

NO MATCH
NO MATCH
https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4