使用正则表达式查找字符串（a href）中的片段

Question

I have the following snipped:

<a href="$click_tracking_url$&landing_url=someurl" border="0" alt=""></a>

What i want is just the someurl . However there are variations such as following:

<a href='$click_tracking_url$&landing_url=someurl' border="0" alt=""></a>

<a target=blank href="$click_tracking_url$&landing_url=someurl" alt=""></a>

I had this regex but doesnt work for variations:

<a href=\".*?landing_url=(.*?)\">

how can i fix it or if there is an easier way to do it?

Answer 1

You did not match all the variations because you did not consider the attributes between href and <a . Try that instead:

Pattern p = Pattern.compile("<a[^>]+href=[\\\\'\\\\\\"].+&landing_url=(.+?)[\\\\'\\\\\\"]");