[英]How to get a reference in a struct of the same struct in my code
I have this struct, but I get some errors when I mention a reference to its own type:我有这个结构,但是当我提到对它自己的类型的引用时,我得到了一些错误:
struct Point {
int x;
int y;
bool isLattice;
Vect2D gradient;
///used only when isLattice is false
Point p00; ///top-left corner
Point p01; ///top-right corner
Point p10; ///bottom-left corner
Point p11; ///bottom-right corner
///the displacement vectors Gradient-this.Vect2D
Vect2D disp00;
Vect2D disp01;
Vect2D disp10;
Vect2D disp11; ///used along the gradient vector of the lattice points
///the Q-s for each corner Q= Disp*G which are going to be used for the interpolation
double q00;
double q01;
double g10;
double q11;
};
I need to know how I should initialize this struct, because this is how I used to do it in the past in other codes.我需要知道我应该如何初始化这个结构,因为这是我过去在其他代码中的做法。 What is the error in this one?
这其中有什么错误?
I would guess you're coming from a managed language我猜你来自托管语言
struct Point {
//...
Point p00;
// ...
}
This is your problem.这是你的问题。 Objects in C++ are NOT references.
C++ 中的对象不是引用。 This puts an instance of Point inside an instance of Point.
这会将 Point 的实例放入 Point 的实例中。 How will that work?
这将如何运作? You could use a pointer, or a reference.
您可以使用指针或引用。
Change改变
Point p00;
to到
Point & p00; // this requires being initialized
// in the constructor initialization list
or maybe或者可能
std::shared_ptr<Point> p00;
Change Point pX;
改变
Point pX;
to Point * pX;
Point * pX;
. .
This way, the code will compile, and you get to initialise the Point pointers using an appropriate constructor.这样,代码将被编译,并且您可以使用适当的构造函数初始化 Point 指针。
为什么不在 Point 实例中使用另一种类型的结构?
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