如何在Linux中解码base64编码的行？

Question

I am trying to read a file & extract only the base64 encoded part. I am doing so by using sed to find the lines between the pattern's 'base64' & '--'.

I am able to do so using

 sed -e '1,/base64/d' -e '/--/,$d' file.txt | sed '/^\s*$/d'

But when i try to decode it using base64 as shown below,

 sed -e '1,/base64/d' -e '/--/,$d' file.txt | sed '/^\s*$/d' | base64 -d

I get an error message as :-

BEGIN:VCALENDAR
METHOD:REQUEST
PRODID:Microsoft Exchangbase64: invalid input

Please let me know what am i doing wrong and is there an alternate, better way to achieve the end result. Any help is appreciated.

Answer 1

I got the issue. the lines in the files were as follows

QkVHSU46VkNBTEVOREFSDQpNRVRIT0Q6UkVRVUVTVA0KUFJPRElEOk1pY3Jvc29mdCBFeGNoYW5nZSBTZ
XJ2ZXIgMjAxMA0KVkVSU0lPTjoyLjANCkJFR0lOOlZUSU1FWk9ORQ0KVFpJRDpBVVMgRWFzdGVybiBTdG 

There was an end line character at the end, so all i had to do was remove it. Hence, now my code looks as below & it works :-

sed -e '1,/base64/d' -e '/--/,$d' _12829640_21.12.-.5p.meeting.room_1485234639532_1.mail | sed '/^\s$/d' | tr -d "\n\r"  | base64 -d