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将Python列表传递给Moviepy模块中的concatenate_videoclips函数

[英]Pass Python list to concatenate_videoclips function in Moviepy module

Purpose: 目的:

  1. Build a python list of video files in a directory 在目录中构建视频文件的python列表
  2. Open video clips (Understood requirement of moviepy) 打开视频片段(需要了解moviepy)
  3. Call combine_clips function and pass 'clips' list (Error occurs here.) 调用Combine_clips函数并传递“片段”列表(此处发生错误。)
  4. Write combined clips to single video file 将合并的剪辑写入单个视频文件

Error: 错误:

"concatenate.py", line 71, in concatenate_videoclips
tt = np.cumsum([0] + [c.duration for c in clips])
AttributeError: 'str' object has no attribute 'duration'"

Script: 脚本:

import os
from moviepy.editor import *

def clips_list():
    clips = []
    for file in os.listdir('.'):
        if file.endswith(".mov"):
            clips.append(file)
    open_clips(clips)

def open_clips(clips):
    for clip in clips:
        VideoFileClip(clip)
    combine_clips(clips)

def combine_clips(clips):
    video = concatenate_videoclips(clips, method='compose')

def output_video(video):
    video.write_videofile('ct_01.mp4')

clips_list()

Question: Why does "concatenate_videoclips()" accept a hardcoded list but fail when I pass it a list. 问题:为什么“ concatenate_videoclips()”接受硬编码列表,但是在将列表传递给它时失败。

You create VideoFileClip(clip) but you don't add to list so you send list with filenames to concatenate_videoclips 您创建了VideoFileClip(clip)但未将其添加到列表中,因此将带有文件名的列表发送到concatenate_videoclips

You need new_list in 你需要new_list

def open_clips(clips):

    new_list = []

    for clip in clips:
        new_list.append(VideoFileClip(clip))

    combine_clips(new_list)

EDIT: shorter: 编辑:较短:

import os
from moviepy.editor import *

clips = []

for filename in os.listdir('.'):
    if filename.endswith(".mov"):
        clips.append(VideoFileClip(filename))

video = concatenate_videoclips(clips, method='compose')
video.write_videofile('ct_01.mp4')

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