golang + grpc：在 GrpcServer 上注册一个服务

Question

I'm working with this example for building a go lang grpc server.

But it seems that I'm missing something - In the example there is a phase of registering a service to the grpc-server but my protoc output has no registration method exported:

s := grpc.NewServer()
pb.RegisterGreeterServer(s, &server{})

Was there a change in the compilation of protobuf3 files?

Am I'm compiling it in the wrong way?

protoc --go_output=. *.proto

And how can I make the service work for the server, It is currently not:

func main() {
    lis, err := net.Listen("tcp", port)
    if err != nil {
        log.Fatalf("failed to listen: %v", err)
    }
    s := grpc.NewServer()
    //register should go here?!
    reflection.Register(s)
    if err := s.Serve(lis); err != nil {
        log.Fatalf("failed to server: %v", err)
    }
}

Answer 1

Am I'm compiling it in the wrong way?

protoc --go_output=. *.proto

Yes. As pointed out in the comment by Wendy Adi , the command-line option to protoc should be --go_out not --go_output and the plugins=grpc option is needed as well (as per the codegen.sh script ). You should be able to use protoc to regenerate the .pb.go file in the helloworld example:

cd $GOPATH/src/google.golang.org/grpc/examples/helloworld
mv helloworld.pb.go helloworld.pb.go.orig
protoc --go_out=plugins=grpc:. helloworld.proto

The greeter_server should compile correctly afterwards:

cd ../greeter_server
go build .

Answer 2

如果使用 grpc 3 使用下面的 cmd

protoc -I=proto --go_out=. --go-grpc_out=. proto/*.proto