I'm working with this example for building a go lang grpc server.
But it seems that I'm missing something - In the example there is a phase of registering a service to the grpc-server but my protoc output has no registration method exported:
s := grpc.NewServer()
pb.RegisterGreeterServer(s, &server{})
Was there a change in the compilation of protobuf3 files?
Am I'm compiling it in the wrong way?
protoc --go_output=. *.proto
And how can I make the service work for the server, It is currently not:
func main() {
lis, err := net.Listen("tcp", port)
if err != nil {
log.Fatalf("failed to listen: %v", err)
}
s := grpc.NewServer()
//register should go here?!
reflection.Register(s)
if err := s.Serve(lis); err != nil {
log.Fatalf("failed to server: %v", err)
}
}
Am I'm compiling it in the wrong way?
protoc --go_output=. *.proto
Yes. As pointed out in the comment by Wendy Adi , the command-line option to protoc
should be --go_out
not --go_output
and the plugins=grpc
option is needed as well (as per the codegen.sh
script ). You should be able to use protoc
to regenerate the .pb.go
file in the helloworld example:
cd $GOPATH/src/google.golang.org/grpc/examples/helloworld
mv helloworld.pb.go helloworld.pb.go.orig
protoc --go_out=plugins=grpc:. helloworld.proto
The greeter_server
should compile correctly afterwards:
cd ../greeter_server
go build .
如果使用 grpc 3 使用下面的 cmd
protoc -I=proto --go_out=. --go-grpc_out=. proto/*.proto
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