[英]How to match the second occurrence in php?
I have a text file: 我有一个文本文件:
; UNIX: "/path1:/path2"
;include_path = ".:/php/includes"
doc_root = "/www/"
user_dir =
extension_dir = "/usr/lib/php"
enable_dl = On
;cgi.force_redirect = 1
;cgi.nph = 1
;cgi.redirect_status_env = ;
cgi.fix_pathinfo=1
;fastcgi.impersonate = 1;
;fastcgi.logging = 0
;cgi.rfc2616_headers = 0
I want to match /www/
here's what I've tried so far: 我想匹配
/www/
这是到目前为止我尝试过的操作:
<?php
$phpini = file_get_contents('/etc/php.ini');
preg_match('/doc_root = ".*/', $phpini, $doc_root);
echo $doc_root[0];
?>
But it prints doc_root = "/www/"
instead of /www/
. 但是它输出
doc_root = "/www/"
而不是/www/
。 How can I do this ? 我怎样才能做到这一点 ?
Not an answer to your exact question, but how about you use parse_ini_file() for files: 不是您确切问题的答案,而是如何对文件使用parse_ini_file() :
$phpini = parse_ini_file('/etc/php.ini');
echo $phpini['doc_root'];
Or for the currently loaded php.ini
: 或对于当前加载的
php.ini
:
echo get_cfg_var('doc_root');
Or the current setting (could have been modified by .htaccess etc.): 或当前设置(可能已被.htaccess等修改):
echo ini_get('doc_root');
Another option would be: 另一种选择是:
echo $_SERVER['DOCUMENT_ROOT'];
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