php regex 从第二次出现字符开始？

Question

I've been fighting with this for a while, i have this string : storage/12426--the sunflower boys--07-09-2014/Authorization letter/Authorization letter--4--09-15-2015--15-39.pdf

and I would love to only get this part 07-09-2014 which lies between the first two slashes.

So far I came up with this: --[^/]* which only gives me --the sunflower boys--07-09-2014 .

How do I get what im looking for?

Answer 1

使用数字\\d匹配：

/^[^/]*\/[^/]*(\d\d-\d\d-\d\d\d\d)\//

Answer 2

You can use a capture group within 2 negated character class :

\/[^\/]*(\d{2}-\d{2}-\d{4})[^\/]*\/

See demo https://regex101.com/r/mL3aF7/1

Answer 3

如果格式一致，您可以拆分/并取第二组，然后拆分--取第三组。

$date = explode('--', explode('/', $str)[1])[2];

Answer 4

You can use match reset \\K based regex:

--[^-]*--\K[^/]*

RegEx Demo