php Regex文件路径|特定字符后的第二个匹配

Question

I trying to extract file patches, without disk letter, that are inside text. Like from AvastSecureBrowserElevationService; C:\\Program Files (x86)\\AVAST Software\\Browser\\Application\\elevation_service.exe [X] AvastSecureBrowserElevationService; C:\\Program Files (x86)\\AVAST Software\\Browser\\Application\\elevation_service.exe [X] extract :\\Program Files (x86)\\AVAST Software\\Browser\\Application\\elevation_service.exe .

My actual regex look like this, but it will stop on any space, which can contains file names.

(?<=:\\)([^ ]*)

The soulution that I figure out is, that I can match first space character after dot, because there is very little chance that there will be some directory name with space after dot, and I will always do fast manual check. But I do not know how to write this in regex

Answer 1

You may use this regex for this purpose:

(?<=[a-zA-Z]):[^.]+\.\S+

RegEx Demo

RegEx Details:

• (?<=[a-zA-Z]) : Lookbehind to assert we have a English letter before :
• : : Match literal :
• [^.]+ : Match 1+ non-dot characters
• \\. : Match literal .
• \\S+ : Match 1+ non-whitespace characters

Answer 2

Here we would consume our entire string, as we collect what we wish to output, and we would preg_replace :

.+C(:\\.+\..+?)\s.+

Test

$re = '/.+C(:\\.+\..+?)\s.+/m';
$str = 'AvastSecureBrowserElevationService; C:\\Program Files (x86)\\AVAST Software\\Browser\\Application\\elevation_service.exe [X]';
$subst = '$1';

$result = preg_replace($re, $subst, $str);

echo $result;

Demo

Answer 3

You can use the following regex:

[A-Z]\K:.+\.\w+

It will match any capital letter followed by : , then any character string ending wit . , followed by at least one word character.

\\K removes from the match what comes before it.

Demo