在while循环内使用break语句时，Python程序输出错误

Question

I am using break statement inside while loop to exit from while loop. But it gives wrong output. I don't know why this occurs. Here is the code I have used:

def func():
    print "You have entered yes"
t='yes' or 'Y' or 'y' or 'Yes' or 'YES'
while True:
    r=raw_input("Enter any number:")
    if t=='r':
        func()
    else:
        break
print "Program End"   

Update:

When I put Yes it should give :
You have entered yes , but control goes to break statement. Why?

Answer 1

You should not use t = 'y' or 'Y' ... in your code because when you use or it checks the validity. Try this code and I am pretty sure it will work.

 def func():
     print "You have entered yes"
 t=('yes', 'Y', 'y', 'Yes', 'YES')
 while True:
     r=raw_input("Enter any number:")
     if r in t:
         func()
     else:
         break
 print "Program End"   

Answer 2

Change

if t=='r':

to

if t==r:

Is that what you want?

Answer 3

First, you're checking if t is equal to the string literal 'r' and not the variable r , so in theory what you want is if t==r

However, this won't work. What you're looking for is a list, like the following:

def func():
    print "You have entered yes"
t= ['yes','Y','y','Yes','YES']
while True:
    r=raw_input("Enter any number:")
    if r in t:
        func()
    else:
        break
print "Program End" 

Answer 4

当执行t =='r'时，您将变量与字符串 r（仅此一个字符）进行比较，而不是与r变量进行比较。