[英]No instance for (Eq TrafficLight) arising from a use of `elem' Possible fix: add an instance declaration for (Eq TrafficLight)
I have an example from Learn You a Haskell for Great Good named 我有一个名为“为善良而学的Haskell”的示例,名为
class Eq1 a where
(===), (=/=) :: a -> a -> Bool
x === y = not $ x =/= y
x =/= y = not $ x === y
data TrafficLight = Red | Yellow | Green
instance Eq1 TrafficLight where
Red === Red = True
Green === Green = True
Yellow === Yellow = True
_ === _ = False
instance Show TrafficLight where
show Red = "Red light"
show Yellow = "Yellow light"
show Green = "Green light"
main = do
print $ Red === Red
print $ Red === Yellow
print $ [Red, Yellow, Green]
print $ Red `elem` [Red, Yellow, Green]
and the first three rows are work, but the last line contains elem
doesn't, got an error: 并且前三行有效,但最后一行包含
elem
则行,但出现错误:
No instance for (Eq TrafficLight) arising from a use of `elem'
Possible fix: add an instance declaration for (Eq TrafficLight)
In the second argument of `($)', namely
`Red `elem` [Red, Yellow, Green]'
I look for the solution how can I add an instance for the marked part, but didn't find hints about the topic, I am new in Haskell so thanks in advance 我正在寻找解决方案,如何为标记的零件添加实例,但是没有找到有关该主题的提示,我是Haskell的新手,所以在此先感谢
Tamas 塔马斯
You have to provide your own elem
. 您必须提供自己的
elem
。 What is elem
's type? elem
的类型是什么?
elem :: Eq a => a -> [a] -> Bool
However, your traffic light doesn't have an Eq
instance. 但是,您的交通信号灯没有
Eq
实例。 It has a Eq1
instance. 它具有一个
Eq1
实例。
You have to write your own elem1
: 您必须编写自己的
elem1
:
elem1 :: Eq1 a => a -> [a] -> Bool
elem1 y xs = -- exercise
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