如何在Python中生成特定的随机数？

Question

I need help with generating a list of specific random numbers using Python. 我需要使用Python生成特定随机数列表的帮助。

I know how to generate a list of random number like this 我知道如何生成这样的随机数列表

import random
number = random.sample(xrange(1,10), 3)

which will generate 3 random numbers between 1 to 10. (Example) 这将生成1到10之间的3个随机数。（示例）

[7, 6, 1]

What I want to do achieve is generating a list of random numbers like this with duplicate value(Example) 我要实现的是生成具有重复值的像这样的随机数列表（示例）

[10000, 30000, 20000, 60000, 100, 3000, 3000, 100, ...]

But using above script like this 但是像这样使用上面的脚本

import random
number = random.sample(xrange(10000,100000), 4)

yields following result (Example) 产生以下结果（示例）

[12489, 43177, 51867, 68831]

Is it possible to do what I want to achieve here? 有可能做我想在这里实现的目标吗？ Thank your answer. 谢谢你的回答。

Answer 1

Something that looks like your example 看起来像您的例子

import random
n1 = random.sample(xrange(1,10), 4)
n2 = random.sample(xrange(2,6), 4)
numbers = [n1i * 10**n2i for n1i, n2i in zip(n1, n2)]

Sample output: 样本输出：

[800000, 7000, 200, 30000]

If you want repeats: 如果要重复：

random.choices(numbers, k=6)

Sample output: 样本输出：

[800000, 7000, 800000, 800000, 7000, 200]

Answer 2

Are you looking for random numbers rounded to the thousands? 您是否正在寻找四舍五入的随机数？

import random
numbers = [1000*x for x in random.sample(xrange(1,100), 4)]

Answer 3

Try this: 尝试这个：

import numpy as np
array1 = np.random.randint(8, size=10)
array2 = np.random.randint(6, size=10)
array3 = (np.power(10, array2)) * array1

Arrays 'array1', 'array2' and 'array3' are (examples): 数组“ array1”，“ array2”和“ array3”是（示例）：

array1 = [2 3 6 7 5 1 1 5 5 7]
array2 = [2 4 1 3 4 5 2 2 4 2]
array3 = [200 30000 60 7000 50000 100000 100 500 50000 700]

array3 is what you want. array3是您想要的。