如何将数值向量切成最大长度为第i个间隔等于n的间隔

Question

For example I have a vector: a = my_function(1000) !

head(a,15)
 [1]  0.4011032  0.4867019  0.9831197  1.1138037  3.2740297  3.7853916  4.6833426  6.9224802  7.5878639
[10]  8.0706788  8.4404792  9.4149317  9.4176043 10.2345215 11.1884374

I want to use cut function(or some alternative) to divide this vector into intervals. BUT I want, that maximum size of each interval will be, for example, 5.

EDITED:

breaks: breaks <- seq(from = 1, by = 4,length.out = 100)

So the first interval is: (1,5] . And first seven variables of a vector falls into this interval. But I want, that size of each intervall to be 5. It means that first 5 variables

[1]  0.4011032  0.4867019  0.9831197  1.1138037  3.2740297 

lies in first interval. And variables 3.7853916 4.6833426 lies in second interval(with length equall 5). How can I do that?

Answer 1

Is this what you are looking for:

a <- rnorm(100)
a <- sort(a)
b <- matrix(data = a, nrow = 10, ncol = 10, dimnames = list(1:10))

Answer 2

You can create a new variable which defines the group of belongness, just sorting the values and labeling them with a number (each one repeated 5 times).

cbind(sort(rnorm(100)), rep(1:20,each=5))

Note thate in rep , instead of 1:20 you should put n/5 being n the number of elements.

If you need to define the intervals, you need only to define theme using the median between the highest value of one set and the minimum one of the following.