[英]How do I “tee” variable number of times in a bash “for loop”?
I understand I can: 我明白我可以:
ssh archive_server -l user -n "cat text.csv"|tee -a text1.csv|tee -a text2.csv|tee....|tee -a text10.csv
Is there a way to do it aa loop? 有没有办法做一个循环?
for i in `seq 1 10`; do
echo $i
tee ???
done
Assuming your shell is really bash (not /bin/sh
), you can build an array (and use a C-style for
loop , which unlike the nonstandard external command seq
, is guaranteed to be available everywhere bash is): 假设你的shell真的是bash(而不是
/bin/sh
),你可以构建一个数组 (并使用一个C风格for
循环 ,这与非标准的外部命令seq
,保证在bash所有地方都可用):
#!/bin/bash
filenames=( )
for ((i=1; i<=10; i++)); do # note that the "10" here can be a variable name
filenames+=( "file$i.txt" )
done
tee -a -- "${filenames[@]}" <text.csv
If you need compatibility with /bin/sh
, it gets a little bit more verbose: 如果你需要兼容
/bin/sh
,它会变得更加冗长:
#!/bin/sh
tee_between() (
prefix=$1; suffix=$2; start=$3; end=$4
set --
i=$(( $start - 1 )); while [ $(( ( i += 1 ) <= end )) -ne 0 ]; do
set -- "$@" "file$i.txt"
done
exec tee -a -- "$@"
)
tee_between "file" ".txt" 1 10 <text.csv
Note: 注意:
set --
modifies the current process's (or, in this case, the current function's) argument list, using that as an array we can dynamically modify. set --
修改当前进程(或者,在本例中是当前函数的)参数列表,使用它作为我们可以动态修改的数组。 tee_between() ( )
instead of tee_between() { }
means that the function runs in a subshell -- a completely separate forked-off process. tee_between() ( )
而不是tee_between() { }
意味着该函数在子shell中运行 - 一个完全独立的分叉过程。 In consequence of this choice, the exec
command will replace only that subshell with a copy of tee
, and not the parent process. exec
命令将仅使用tee
的副本替换该子shell,而不是父进程。 You don't need a loop. 你不需要循环。
tee
can be given multiple filename arguments, so just give all the output files at once: tee
可以被赋予多个文件名参数,所以只需一次提供所有输出文件:
cat text.csv | tee -a text{1..10}.csv
If the number of files is dynamic, you can use a loop in $()
to insert the filenames into the command line: 如果文件数是动态的,您可以使用
$()
的循环将文件名插入命令行:
cat text.csv | tee -a $(
for i in $(seq 1 $filecount); do
echo text$i;
done)
Just make sure that you don't have any whitespace in the output filename prefix, as the spaces will be treated as argument delimiters. 只需确保输出文件名前缀中没有任何空格,因为空格将被视为参数分隔符。
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