[英]Why doesn't this array prototype work?
I don't understand why array b[1] does not use f as a getter and setter yet array a does. 我不明白为什么数组b [1]不使用f作为getter和setter而数组a却使用f。 yet both are arrays.
但这两个都是数组。 what am I missing here?
我在这里想念什么?
function f(){
print("in f");
}
Object.defineProperty(Array.prototype, "0",
{ get : f, set:f});
var a=[];
var b=[1];
a[0]; // prints f
a[0]=1; //prints f
b[0]; // no print
b[0]=1; // no print
console.log("a is an array " + Array.isArray(a)); //a is an array true
console.log("b is an array " + Array.isArray(b));//b is an array true
var a = []
does one thing: it sets a
as an instance of a new Array
but without any members, so the prototype[0]
is inherited. var a = []
做一件事:它将a
设置为new Array
的实例,但是没有任何成员,因此prototype[0]
被继承。
var b = [1]
does two things: it sets b
as an instance of a new Array
(as with a
), but then sets subscript [0] = 1
directly (bypassing JavaScript's prototype system), which means [0] = 1
overwrites the " 0
th" property, thus avoiding your defineProperty
in prototype[0]
entirely. var b = [1]
做两件事:将b
设置为new Array
的实例(与a
),然后直接设置下标[0] = 1
(绕过JavaScript的原型系统),这意味着[0] = 1
覆盖 “第0
个”属性,从而完全避免了prototype[0]
defineProperty
。
This works the same way with objects: 这与对象的工作方式相同:
Object.defineProperty( Object.prototype, "foo", { get: f, set: f } );
var a = {};
a.foo = 1; // will print "in f"
var b = { foo: 'a' }
b.foo = 1; // will not print "in f"
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