[英]argument pass in powershell function
I am facing a problem to add loop count with a variable and than pass it to function and print details. 我面临的一个问题是添加带有变量的循环计数,然后将其传递给函数并打印详细信息。 please suggest your wise suggestion.
请提出您的明智建议。
My code is shown below: 我的代码如下所示:
function CheckErrorMessage {
[CmdletBinding()]
Param (
[Parameter(Mandatory = $true, Position = 0)]
[ValidateNotNullOrEmpty()]
$Plugin
, [Parameter(Mandatory = $true, Position = 1)]
[ValidateNotNullOrEmpty()]
$Report_Decission
)
switch ($Plugin){
'plugin-1' {
$Report_Decission
}
'plugin-2' {
$Report_Decission
}
Default {
}
}
}#functions ends here
$test_1 = "no report"
$test_2 = "with report"
for($i=1; $i -ne 3; $i++){
CheckErrorMessage 'plugin-1' "$test_$i" # i want to sent $test_1 or $test_2 from here
CheckErrorMessage 'plugin-2' "$test_$i"
}
when i run this, it prints 当我运行它时,它会打印
1
1
2
2
but i want the output like: 但我想要这样的输出:
no report
no report
with report
with report
Thanks in advance. 提前致谢。
You have to actually invoke that expression, so the variable expands, and you have to escape $
with `, so it doesnt try to expand it 您必须实际调用该表达式,变量才能展开,并且必须使用`转义
$
,因此它不会尝试扩展它
CheckErrorMessage 'plugin-1' $(iex "`$test_$i")
Invoke-Expression: 调用表达:
The Invoke-Expression cmdlet evaluates or runs a specified string as a command and returns the results of the expression or command. Invoke-Expression cmdlet评估或运行指定的字符串作为命令,并返回表达式或命令的结果。 Without Invoke-Expression, a string submitted at the command line would be returned (echoed) unchanged.
如果没有Invoke-Expression,则在命令行提交的字符串将原样返回(回显)。
Reference: https://msdn.microsoft.com/en-us/powershell/reference/5.1/microsoft.powershell.utility/invoke-expression 参考: https : //msdn.microsoft.com/en-us/powershell/reference/5.1/microsoft.powershell.utility/invoke-expression
edit: another way to do that (probably better and safer) by Mathias 编辑:另一种方法来做到这一点(可能更好,更安全),作者是Mathias
$ExecutionContext.InvokeCommand.ExpandString("`$test_$i")
An alternative method that is a little more understandable is to use Get-Variable
. 一种更容易理解的替代方法是使用
Get-Variable
。
...
$test_1 = "no report"
$test_2 = "with report"
for($i=1; $i -ne 3; $i++) {
CheckErrorMessage 'plugin-1' (Get-Variable "test_$i").Value
CheckErrorMessage 'plugin-2' (Get-Variable "test_$i").Value
}
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