[英]How to for each loop through two columns in a dataframe?
I have a dataframe containing 7 columns and I want to simultaneously loop through two of them to compare the values in each row. 我有一个包含7列的数据框,我想同时遍历其中的两列以比较每一行中的值。 This is my for loop header, where watchCol and diaryCol are column numbers:
这是我的for循环标题,其中watchCol和diaryCol是列号:
for watch, diary in df.iloc[:, watchCol], df.iloc[:, diaryCol]:
When I run this, I get the following error on that line: 运行此命令时,在该行上出现以下错误:
ValueError: too many values to unpack (expected 2)
ValueError:太多值无法解包(预期2)
What am I doing wrong? 我究竟做错了什么?
Thanks 谢谢
EDIT: 编辑:
Both columns contain datetimes. 两列均包含日期时间。 I need to compare the two values, and if the difference is within a certain range, I copy the value from the watchCol into another column, otherwise I move to the next row.
我需要比较两个值,如果差异在一定范围内,则将值从watchCol复制到另一列,否则移至下一行。
If you're trying to compare entries row by row, try this: 如果您要逐行比较条目,请尝试以下操作:
import pandas as pd
df = pd.DataFrame({"a": [2, 2, 2, 2, 2], "b": [4, 3, 2, 1, 0]})
df["a greater than b"] = df.apply(lambda x: x.a > x.b, axis=1)
print df
a b a greater than b
0 2 4 False
1 2 3 False
2 2 2 False
3 2 1 True
4 2 0 True
That said, if you did want to loop through the elements row by row: 也就是说,如果您确实想逐行遍历元素:
for a, b in zip(df.iloc[:, 0], df.iloc[:, 1]):
print a, b
2 4
2 3
2 2
2 1
2 0
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