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为什么哈希 <const char*> 为字符串而不是字符串变量工作?

[英]Why does hash<const char*> work for strings but not string variables?

My question is why does the following code work 我的问题是为什么以下代码有效

hash<const char*> PassHash;

cout << PassHash("Hello World");

But this code wont compile. 但是这段代码不会编译。

hash<const char*> PassHash;
string password;
password = "Hello World";

cout << PassHash(password);

In Code Blocks I get this error 在代码块中,我收到此错误

error: no match for call to '(__gnu_cxx::hash<const char*>) (std::string&)'|

std::hash has a definition similar to the following std::hash具有类似于以下内容的定义

template<typename T>
struct hash {
  size_t operator()(const T& value) const {
    ...
  }
}

So it's trivial that std::hash<const char*> template instantiation defines an operator() which accepts a const char* , but you are passing a std::string which is a different type. 因此, std::hash<const char*>模板实例化定义一个operator()可以接受const char* ,这很简单,但是您要传递另一种类型的std::string

Just use directly std::string for your password variable and std::hash<std::string> instead. 只需直接使用std::string作为您的密码变量,而直接使用std::hash<std::string>

There is no implicit conversion from std::string to const char* which would be required to make your example work. std::stringconst char*没有隐式转换,这将使您的示例正常工作。

You may call string::c_str() to explicitly do this "conversion"... 您可以调用string::c_str()来显式执行此“转换” ...

hash<const char*> PassHash;
string password;
password = "Hello World";

cout << PassHash(password.c_str());

... but this will only calculate the hash of the string pointer because there is no specialization for hash<const char*> ! ...但是这只会计算字符串指针哈希值,因为hash<const char*>没有特殊化! So this only matches the generic pointer specialization hash<T*> . 因此,这仅与通用指针专门化hash<T*>匹配。

What you propably really want is hash over the entire character array of the string, so if one character of the string changes, you (most likely) get a different hash value. 您可能真正想要的是在字符串的整个字符数组上进行哈希处理 ,因此,如果字符串中的一个字符发生更改,您(很可能)将获得不同的哈希值。

For this you could use the hash<std::string> specialization. 为此,您可以使用hash<std::string>专业化。 This works for both const char* and std::string arguments as expected, because std::string has a conversion constructor that takes a const char* . 这可以按预期对const char*std::string参数都起作用,因为std :: string具有采用const char*的转换构造const char*

Example: 例:

const char* password1 = "Hello World";
string password2 = "Hello World";

hash<const char*> charPtrHasher;

// This only calculates a hash from the value of the pointer, not from 
// the actual string data! This is why you get a different hash for each.
cout << "Test 1:\n";
cout << charPtrHasher(password1) << endl << charPtrHasher(password2.c_str()) << endl;

hash<std::string> stringHasher;

// This correctly calculates the hash over all characters of the string!
cout << "\nTest 2:\n";
cout << stringHasher(password1) << endl << stringHasher(password2) << endl;

Live Demo: http://coliru.stacked-crooked.com/a/047c099f5dcff948 现场演示: http : //coliru.stacked-crooked.com/a/047c099f5dcff948

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