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用另一个小标题中的字符向量设置小标题的列

[英]subsetting columns of a tibble with a character vector from another tibble

I have two tibbles 我有两个小题词

>a.tibble

names other
 a      0
 c      0
 d      0

>b.tibble

a   b   c   d  e
1   1   1   1  1
1   1   1   1  1

I would like to use names <- select(a.tibble,names) to subset b.tibble to make c.tibble : 我想使用names <- select(a.tibble,names)来子集b.tibble以使c.tibble

>c.tibble

a   c   d  
1   1   1   
1   1   1 

It is important that I subset by names because in reality I have many names to subset a large tibble. 我的子集是非常重要names ,因为在现实中我有很多名称子集大tibble。 This makes it so the usual select(b.tibble,-c(b,e)) or other "manual" entry of column names is not possible. 这样一来,通常的select(b.tibble,-c(b,e))或其他“手动”列名称的输入就不可能了。

Data 数据

library(tibble)
a.tibble = tibble(names = c("a","c","d"), other = 0)
b.tibble = tibble(a = rep(1,2), b = 1, c = 1, d = 1, e = 1)

@ytk有一个对我b.tibble[, names(b.tibble) %in% a.tibble$names]的答案b.tibble[, names(b.tibble) %in% a.tibble$names]

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