如果/不检查输入内容是否为输入的一部分，如何进行输入？

Question

Ok, Im new to Python, as in only been coding in it for ~2.5 weeks. Please remember that in your answers. :D.

Im currently trying to make a program, as actually MAKING programs with stuff Iv been learning online helps me to learn it (Extremely basic Ubuntu terminal emulator, why not ;p) and I need to make an input that checks if something in an if/else statement is in the input.

Example:

 input1 = input("test@ubuntu:~$")
 if input1 == "sudo":
     input2 = input("[sudo] enter password for test:")

But have the if statement trigger if sudo/cd/anything is mentioned ANYWHERE in the input. If someone put in "sudo cd / " it would trigger because the input has Sudo in it. Again, Im new to this language as a whole, so please no "duh, you just do this, you should have known that" answers please!

Answer 1

if "sudo" in input1:
    ...

This checks substring inclusion as well as appearance in a sequence (list, tuple, string, etc.).

For more general use, to find if any disallowed term is in the input:

bad_list = [
    "sudo",
    "cd",
    "/",
    "anything"
]

if any([word in input for word in bad_list]):

The any (logical or) and all (logical and) operators go through a list of values, taking them as Booleans (checking the "truthy" property of each element). The stuff in brackets is called a "list comprehension", and it's a way of building a list by description -- sort of coding a for loop inside a list.

Answer 2

@Prune's answer is what you asked for. But for what you want to do, I believe .starstwith('sudo') could be helpful.

if input1.strip().starstwith('sudo'):
   ...

Because otherwise, if you run something like echo 'sudo' for example, it'll ask you the password.

Note: the .strip removes any spaces/line break at the beginning or at the end of the string