类型转换错误：Python

Question

I have just started to learn python and I am getting the following error for the function I have written. I think it's due to typecast but I am not sure how to correct.

Error I get:

File "validate.py", line 23, in keygen
(array3[0]) = int(array2[0]) ^ int(array2[n-1],8)
ValueError: invalid literal for int() with base 10: '0xd4d745957e685d08L'

Function:

def keygen(array2):
    n = len(array2)
    array3[0] = int(array2[0]) ^ int(array2[n-1],8)
    i = 1
    while(i != n):
        array3[i] = array2[i] ^ array3[i-1]
        i = i + 1
    printarray(array3)

Here array2 is an array of hexadecimal value as below:

 array2: [0xd4d745957e685d08L,
          0x9a542ff214aa011cL,
          0x1289806cf20e724L,
          0x20dd453feea65bf4L,
          0x209ab70c8a12a914L,
          0xa16cde82faf9de54L,
          0x99c60b68361506d4L,
          0x5b98ffaaf450a3d4L,
          0xe5c75e967b0bbbe9L]

array3 is an empty array where new values are inserted.

Answer 1

Since array2 contains hex values you have to use int(array2[0], 16) to convert it into integer value. you will need to remove the trailing L from the array or use something like below.

array3[0] = int(str(array2[0])[:18], 16) ^ int(str(array2[n-1])[:18], 16)