如何拆分> 1位整数列表并从该数字创建列表？ 蟒蛇

Question

Say I have list a = [23, 2] . I need to split every element in list and then combine them to one list. So result be like a = [2, 3, 2] What I have for now is:

list = [int(i) for i in str(map([], map(lambda x: x*2, list(reversed(numlist))[1::2])))]

Where map(lambda x: x*2, list(reversed(numlist))[1::2]))) is the list of even indexed numbers (2, 4, 6...) each multiplied by 2.

It gives me: ValueError: invalid literal for int() with base 10: '<' on this line.

Answer 1

>>> map(int, ''.join(map(str, a)))
[2, 3, 2]

Answer 2

Using two level List Comprehension:

a = [23, 2]
digits = [ int(x) for num in a for x in str(num) ]

Answer 3

You can first change list to string then change this string back to integer list. Here is an example.

a = [23, 2]
a = [int(j) for j in ''.join([str(i) for i in a])]
print(a)