[英]Get count for the max date [MYSQL]
I have to find the count of customers that in their latest account (capital*) balance (they might have multiple accounts), balance_value is over than 1.000.000 我必须找到在其最近的帐户(资本*)余额(他们可能有多个帐户)中,balance_value超过1.000.000的客户数
*capital: balance_type ='Capital' * capital:balance_type ='Capital'
I guess my Query for that returns wrong results and it its inefficient 我猜我的查询返回错误的结果,它效率低下
SELECT COUNT(DISTINCT customer.customer_id) AS customers
FROM balance INNER JOIN account ON balance.account_id = account.account_id
INNER JOIN contract ON account.contract_id = contract.contract_id
INNER JOIN customer ON customer.customer_id = contract.customer_id
WHERE balance.balance_type like '%Capital%' AND balance.balance_value > 1000000
ORDER BY balance.balance_date DESC
i guess that i need some help :S 我想我需要一些帮助:S
Download sample data (move Data folder to C:/) and script to create the schema https://drive.google.com/file/d/0BxVNamixm4W2SHVadndtWkNBajg/view?usp=sharing 下载示例数据(将数据文件夹移动到C:/)和脚本以创建架构https://drive.google.com/file/d/0BxVNamixm4W2SHVadndtWkNBajg/view?usp=sharing
what is your query result? 您的查询结果是什么?
what kind of 'correct' result did you expect? 您期望得到什么样的“正确”结果?
fyi, 仅供参考,
group by customer_id will make it faster than distinct does 按customer_id进行分组将使其速度更快
if you know the exact capital word, would better using EQUAL TO / = rather than LIKE (= is faster than LIKE) 如果您知道确切的大写字母,最好使用EQUAL TO / =而不是LIKE(=比LIKE更快)
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