[英]Apply a function to every column of a dataframe in pandas
I have this: 我有这个:
df = DataFrame(dict(person= ['andy', 'rubin', 'ciara', 'jack'],
item = ['a', 'b', 'a', 'c'],
group= ['c1', 'c2', 'c3', 'c1'],
age= [23, 24, 19, 49]))
df:
age group item person
0 23 c1 a andy
1 24 c2 b rubin
2 19 c3 a ciara
3 49 c1 c jack
what I want to do, is to get the length of unique items in each column. 我想要做的是获得每列中唯一项目的长度。 Now I know I can do something like:
现在我知道我可以这样做:
len(df.person.unique())
for every column. 对于每一列。
Is there a way to do this in one go for all columns? 有没有办法一次性完成所有列?
I tried to do: 我试着这样做:
for column in df.columns:
print(len(df.column.unique()))
but I know this is not right. 但我知道这不对。
How can I accomplish this? 我怎么能做到这一点?
you want pd.Series.nunique
你想要
pd.Series.nunique
df.apply(pd.Series.nunique)
age 4
group 3
item 3
person 4
dtype: int64
You can use: 您可以使用:
for column in df:
print(len(df[column].unique()))
4
3
3
4
Or: 要么:
for column in df:
print(df[column].nunique())
4
3
3
4
You can the number of unique items in each column as: 您可以将每列中的唯一项目数量设置为:
for column in df.columns:
print(len(df[column].unique()))
为什么不是这样的,
df.nunique()
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