[英]% Chance, is this code efficient and correct?
public class Spell {
// chance = (0, 100>
private int chance;
public void execute() {
if (chance < 100) {
/*
chance:80
random:40 ... if(true) ... succeed
chance:80
random:80 ... if (true) ... failed
chance:80
random:81 ... if (true) ... failed
chance:79
random:80 ... if (false) ... succeed
chance:66
random:<0,65> (66 numbers) ... if (false) ... succeed
random:<66,99> (34 numbers) ... if (true) ... failed
*/
if (chance <= (int) (Math.random() * 100)) {
System.err.println("failed");
return;
}
}
System.out.println("succeed");
}
//Test
public static void main(String[] args) {
Spell spell = new Spell();
spell.chance = 80;
spell.execute();
}
}
Is this correct way to calculate chance? 这是计算机会的正确方法吗? I need certain things to happen chance % of times. 我需要一定的事情发生的时候偶然 %。 I wonder whether I did some mistake here or whether it works. 我想知道我是否在这里犯了一些错误或是否有效。
Let's say we have chance = 80, I need it to succeed in 80% of times and fail in 20% of time. 假设我们有机会= 80,我需要它在80%的时间内取得成功,并在20%的时间内失败。 There are souts for that in code, where I will add a function later. 在代码中有一些souts,我稍后会添加一个函数。
From the mathematical point of view your idea is correct. 从数学的角度来看,你的想法是正确的。 You fix a segment [0, 100) and get random number with equal distribution. 您修复了一个段[0,100]并获得具有相同分布的随机数。 The probability that generated number falls into segment [0,80) is 80%. 生成的数字落入段[0,80]的概率为80%。
Taking into account suggestions in comments to your question, the code could look like this: 考虑到对您的问题的评论中的建议,代码可能如下所示:
import java.util.Random;
public class Spell {
private int chance;
private Random rnd = new Random(System.currentTimeMillis());
public Spell(int chance) {
//TODO: Check that chance is inside [0, 100]
this.chance = chance;
}
public void execute() {
if (rnd.nextInt(100) <= chance)
System.out.println("succeed");
else
System.err.println("failed");
}
}
Finally, you will see "succeed" printed with chance
probability. 最后,您将看到以chance
概率打印的“成功”。
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