Javascript替换数组中的第6个冒号

Question

I have some problems with replacing every 6th colon in my array. Have tried something with Regex, but that doesn't seem to work. I have red other questions were people are using nth and then set this variabele to the index you want to replace, but can't figure out why that isn't working. I used the join function to replace the ',' in my array with ':'.

arrayProducts[i] = arrayProducts[i].join(':');

When i use console.log(arrayProducts); this is my result:

F200:0:0.0000:1:100:0:1:KPO2:0:0.0000:1:200:0:2:HGB1:0:0.0000:1:300:0:3

This is what I want:

F200:0:0.0000:1:100:0:1,KPO2:0:0.0000:1:200:0:2,HGB1:0:0.0000:1:300:0:3

Thanks for reading!

Edit: F200, KP02 and HGB1, could also be numbers / digits like: 210, 89, 102 so the :[AZ] method from regex doesn't work.

Answer 1

You can just count the number of colon occurences and replace every nth of them.

 var str = 'F200:0:0.0000:1:100:0:1:KPO2:0:0.0000:1:200:0:2:HGB1:0:0.0000:1:300:0:3', counter = 0; res = str.replace(/:/g, function(v) { counter++; return !(counter % 7) ? ',' : v; }); console.log(res); 

Answer 2

A regex solution is viable. You can use a function as the second parameter of the .replace method to make full use of backreferences.

 var str = 'F200:0:0.0000:1:100:0:1:KPO2:0:0.0000:1:200:0:2:HGB1:0:0.0000:1:300:0:3'; str = str.replace(/((?:[^:]*:){6}(?:[^:]*)):/g, function() { var matches = arguments; return matches[1] + ','; }); console.log(str); 

Answer 3

What you are looking for is to split over the following expression :[AZ] (assuming that your rows always start with this range)

a simple solution could be:

mystring.split(/:[A-Z]/).join(',')

/:[AZ]/ matches any : followed by a uppercase letter

Answer 4

maybe you can try this approach, loop your array and join it manually, something like :

     var strarr = "F200:0:00000:1:100:0:1:KPO2:0:00000:1:200:0:2:HGB1:0:00000:1:300:0:3";
     var arr = strarr.split(":")

      var resStr = "";

       for(var i = 0; i < arr.length; i++)
       {
           if(i > 0 && i%7 == 0)
               resStr = resStr + ","  + arr[i]
           else
               resStr =  resStr + ( resStr == "" ? "" : ":") + arr[i];
        }

        console.log(resStr);

Answer 5

You could use replace with a look for six parts with colon and replace the seventh.

 var string = 'F200:0:0.0000:1:100:0:1:KPO2:0:0.0000:1:200:0:2:HGB1:0:0.0000:1:300:0:3', result = string.replace(/(([^:]*:){6}[^:]*):/g, '$1,'); console.log(result); 

Answer 6

Another solution (based on the number of iteration)

using map method:

str.split(':').map((v, i) => (i % 7 === 0 ? ',' : ':') + v ).join('').slice(1)

using reduce method:

str.split(':').reduce((acc,v, i) =>  {    
    return acc +  (i % 7 === 0 ? ',' : ':' ) + v ;
}, '').slice(1)

Note: arrow expression does not work on old browsers