Javascript Regex取代第6次出现; （分号）with; \\ n（分号和换行符）

Question

string = "bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;bla;";

bla is wildcard.

I want to update my string by inserting a newline (\\n) at every 6th occurrence of a semicolon (;)

I have been trying to do this with regex:

---

var myregexvar = textbox.value;

myregexvar = myregexvar.replace(/\u003b.*\u003b.*\u003b.*\u003b\b/, /$1\n/);

---

/u003b is the unicode character code for ';'

it doesnt work. help!

Answer 1

Try matching (([^;]*;){5}[^;]*); and replacing with $1\\n .

The first grouped expression ([^;]*;){5} looks for five bla; . Then [^;]* takes the sixth bla (without the ;). All of that gets grouped into $1 . Then the last semicolon is matched separately, so that it is left out and replaced with the \\n from the replacing expression.

Edit

Didn't realize you wanted to add \\n after every sixth semicolon, not replace. You can use this simpler match expression: ([^;]*;){6} .

Answer 2

hopefully this algorithm may help u

$occurance = 6;
$count = 0;
while (/\u003b/gi) {
    if (++$count == $occurance) {
        myregexvar.replace(/\u003b/, /\n/);        
    }
}